Objective: CD's have very small grooves on them which make it possible to store music on them. Measure the distances between the groves on a CD by using a laser and diffraction.
Equipment:
Procedure: Arrange the laser and screen so that the laser points through the hole in the screen and hits the CD with nearly normal incidence. (we used a white board to help mount the CD.
Move the CD around as needed in order to see a diffraction pattern coming from the CD to the screen. Make it so that the first order maxima will appear on the screen on either side of the hole the laser is coming through. (the zero order maxima strikes the hole so it is not seen. Once this happens the distance between the screen and the CD is measured, L, and the distance from the hole to the first order maxima is measured, x, (this part was done by marking on the screen the location of the maxima and measuring the length and dividing by 2). Also note the wavelength of the laser.
λ=633 nm L=3.8 ± 0.02 cm 2x= 2.5 ± 0.1 cm
Using these calculations it is seen that our error is high from the standard manufacturer's standard value of 1600 nm. This error is accredited to the the fact that our experiment was not stable. We couldn't get the diffraction to show on our screen so for the experiment we held the CD (off the table) in order to get the diffraction to show on the screen. As a result our measurements were not very accurate because the CD was moving around slightly. But on the low side of our uncertainty we came up with a 9.31% deviation from the standard value.
Friday, October 26, 2012
Relativity in Length Active Physics
Again using Active Physics, concepts from relativity are explored. This time Length contraction is explored.
http://media.pearsoncmg.com/bc/aw_young_physics_11/pt2a/Media/ModernPhysics/1702RelOfLength/Main.html
In this experiment light is going in the same direction as motion.
The time measurement of a round trip for the ray in the lights frame is independent of weather the light clock is moving relative to the earth or not.
The round trip time interval as measured on a stationary point on the earth will be longer than the frame of reference of the time clock.
If the length of the light clock were 1000m (propper length) to find the length in the second frame we can use the relation, the length in any frame is given by the proper length divided by the Lorentz Factor. If the Lorentz factor were 1.3 the the length of the clock in the second frame would be(1000)m/1.3=769m
http://media.pearsoncmg.com/bc/aw_young_physics_11/pt2a/Media/ModernPhysics/1702RelOfLength/Main.html
In this experiment light is going in the same direction as motion.
The time measurement of a round trip for the ray in the lights frame is independent of weather the light clock is moving relative to the earth or not.
The round trip time interval as measured on a stationary point on the earth will be longer than the frame of reference of the time clock.
- As mentioned in the previous lab, time dilation in one frame is the product of the Lorentz factor and the proper time. This is consistant with what is observed here.
If the length of the light clock were 1000m (propper length) to find the length in the second frame we can use the relation, the length in any frame is given by the proper length divided by the Lorentz Factor. If the Lorentz factor were 1.3 the the length of the clock in the second frame would be(1000)m/1.3=769m
Relativity in Active Physics
Using Acive Physics from the following website, I explored the effects or time dilation near the speed of light by varying the value of the gamma value (essentially changing velocity).
http://media.pearsoncmg.com/bc/aw_young_physics_11/pt2a/Media/ModernPhysics/1701RelOfTime/Main.html
The length traveled by the light is longer in the second frame of reference (the one not moving with the light).
Because the speed of light is constant in all frames of reference the time it takes in the second frame of reference to complete a cycle is longer than the time in the initial frame. Specifically, according to the simulation, if the mirrors are moving at gamma=1.4 the time difference is 2.73 µs.
In the frame of reference of the time clock, the time required to complete a round trip is independent of weather the mirrors are moving or not.
The difference in light pulse travel time between the earth's timers and the light clock's timers will decrease as the time clock's speed slows down and becomes closer to that of earth's.
The equation for this effect (time dilation) is Δt = γΔtproper where the proper time is the time in the frame of the light clock. for γ = 1.2 the time seen in the second frame should be 8.00 µs which agrees with the experiment when changing γ to 1.2.
If the time for the observer in earth's frame is 7.45 µs then using the same equation we get gamma to be about 1.12. When the program is used and 1.12 is used then the timing on the earth's frame is consistent with this.
http://media.pearsoncmg.com/bc/aw_young_physics_11/pt2a/Media/ModernPhysics/1701RelOfTime/Main.html
The length traveled by the light is longer in the second frame of reference (the one not moving with the light).
Because the speed of light is constant in all frames of reference the time it takes in the second frame of reference to complete a cycle is longer than the time in the initial frame. Specifically, according to the simulation, if the mirrors are moving at gamma=1.4 the time difference is 2.73 µs.
In the frame of reference of the time clock, the time required to complete a round trip is independent of weather the mirrors are moving or not.
The difference in light pulse travel time between the earth's timers and the light clock's timers will decrease as the time clock's speed slows down and becomes closer to that of earth's.
The equation for this effect (time dilation) is Δt = γΔtproper where the proper time is the time in the frame of the light clock. for γ = 1.2 the time seen in the second frame should be 8.00 µs which agrees with the experiment when changing γ to 1.2.
If the time for the observer in earth's frame is 7.45 µs then using the same equation we get gamma to be about 1.12. When the program is used and 1.12 is used then the timing on the earth's frame is consistent with this.
Saturday, October 13, 2012
Measuring a Human Hair
Objective: To measure the thickness of a human hair using a laser and micrometer.
Mount the laser so it shines over the hair and an interference pattern on the vertical surface. The wavelength of the laser is given to be 633nm. Measure the distance between maximum on the diffraction pattern (y) and record the order of the maximum (m).
Equipment:
- Laser
- Meter Stick
- Note Card
- Hair
- Micrometer
Mount the laser so it shines over the hair and an interference pattern on the vertical surface. The wavelength of the laser is given to be 633nm. Measure the distance between maximum on the diffraction pattern (y) and record the order of the maximum (m).
It was easier to mark the maximum and and measure the marks afterwards.
The equation used to determine the diameter was:
d=λLm
y
The measurement obtained from this was compared to the measurement obtained from measuring a hair with a micrometer.
The Length of separation was 1.00 ± 0.01m
Sample 1: y= 3.1 ± 0.1cm
m=6
Diameter = 0.000123 ± 0.000005 m
Sample 2: y= 3.3 ± 0.1cm
m=4
Diameter = 0.0000767 ± 0.0000032 m
Sample 3: y= 1.2 ± 0.2cm
m=1
Diameter = 0.0000528 ± 0.00001.11 m
The diameter measured was on the correct order of magnitude as expected of the diameter of hair. Using the micrometer was slightly difficult but it gave similar values. For sample 1 the micrometer gave a value of 0.0002 m. This is a error of 48%. The micrometer is less accurate because the minimum increment of measurement is a tenth of a millimeter The laser method can better measure small lengths because it can more accurately measure the parameters needed and obtain much smaller values.
Wednesday, October 3, 2012
Lenses
Objective: To observe characteristics of a converging lens when the object is placed on one side of the lens and the real, inverted image is placed on the other side of the lens.
Equipment:
- socket lamp with V-shaped filament
- Large converging lens
- masking tape
- Lens Holder
- piece of cardboard (or other flat surface)
- Track for lens
- Meter stick
The focal length was recorded by taking a source that was infinitely far (the sun) and arranging it around to find a point where the image was focused. A meter stick was used to find the distance between the lens and the focused image. This was 0.0485 ±0.0030 m.
The following was set up by placing the lens into the lens holder and creating a track for the lens (using a meter stick and some stands).
The length of the arm of the image from the circle to the end of the line was take as the object image (9.2±2.0 cm). We place the image about 1.5 focal lengths away and used the cardboard to focus the resulting image. The image height and distance from the lens was recorded. From this the magnification could be found by dividing the image height by the object height. (If the lens was rotated the image remained the same). The image was always inverted.
This was repeated for various focal lengths.
Object Distance | Image Distance | Image Height | Object Height. | Magnification | |||
1 | 25 | 6 | 2.1 | 12 | 0.175 | ± | 0.02 |
2 | 20 | 5.4 | 2.9 | 12 | 0.242 | ± | 0.02 |
3 | 15 | 6.4 | 3.8 | 12 | 0.317 | ± | 0.02 |
4 | 10 | 8.6 | 7.3 | 12 | 0.608 | ± | 0.03 |
5 | 7.5 | 7.5 | 13 | 12 | 1.083 | ± | 0.04 |
All of these values were measured in cm. The object distance and image height values were plus or minus 0.2cm while the image distance was about plus or minus 1.5cm.
Data Analysis: If the object distance was less then one focal point the object height was too great to record. A graph of image distance vs object distance was made and showed a nonlinear relationship. But when we graphed the inverse of negative object distance vs the inverse of image distance we got a somewhat linear relation (within experimental error arising from difficulties in finding the exact image distance). Do to it being an outlyer the fifth data point was removed from the calculation of the plot.
The y intercept was 0.2208 which represents the inverse of image distance as the object distance reaches infinity. This is the inverse of the focus! The relationship between Inverse object distance (x) and inverse of image distance (y) is given in the equation in the above image
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